4y^2-16y+16=60^2

Solution for 4y^2-16y+16=60^2 equation:

4y^2-16y+16=60^2

We move all terms to the left:

4y^2-16y+16-(60^2)=0

We add all the numbers together, and all the variables

4y^2-16y-3584=0

a = 4; b = -16; c = -3584;
Δ = b2-4ac
Δ = -162-4·4·(-3584)
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-240}{2*4}=\frac{-224}{8}
=-28
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+240}{2*4}=\frac{256}{8}
=32
$